Toán Lớp 6: Tính A rồi tìm x:
A=1/1.2+1/2.3+…+1/99.100
|A|=0
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 6: Tính A rồi tìm x:
A=1/1.2+1/2.3+…+1/99.100
|A|=0
Comments ( 2 )
A=1/1.2+1/2.3+…+1/99.100
A=1-1/2+1/2-1/3+…+1/99-1/100
A=1-1/100
A=100/100-1/100
A=99/100
Thay A vào |A|=x+0 ta có:
|99/100|=x
x=|99/100|
=>\(\left[ \begin{array}{l}x=\frac{99}{100}\\x=\frac{-99}{100}\end{array} \right.\)
Vậy x in{99/100;-99/100}