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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: thành nhân tử 27X ³-27X ²+3X+1

Toán Lớp 8: thành nhân tử
27X ³-27X ²+3X+1

Comments ( 2 )

  1. 27x³ – 27x² + 3x + 1
    = 27x³ – 9x2 – 18x2 + 6x – 3x + 1
    = 9x2 (3x – 1) – 6x (3x – 1) – (3x – 1)
    = (3x – 1) (9x2 – 6x – 1)
    = (3x – 1) [(9x2 – 6x + 1) − 2]
    = (3x – 1) {[(3x)2 – 2.3x.1 + 12) – 2]}
    = (3x – 1) [(3x – 1)2 − 2]
    = (3x – 1) (3x – 1 – $\sqrt[]{2}$ ) (3x – 2 + $\sqrt[]{2}$ )

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     27x^3-27x^2+3x+1
    =27x^3-18x^2-9x^2-3x+6x+1
    =27x^3-9x^2-18x^2+6x-3x+1
    =9x^2(3x-1)-6x(3x-1)-(3x-1)
    =(3x-1)(9x^2-6x-1)

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222-9+11+12:2*14+14 = ? ( )

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