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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Cho `a + b + c +d = 0` Chứng minh rằng `a^3 + b^3 + c^3 + d^3 = 3(b + c)(ad – bc)` Cần gấp ạ

Toán Lớp 8: Cho a + b + c +d = 0
Chứng minh rằng a^3 + b^3 + c^3 + d^3 = 3(b + c)(ad – bc)
Cần gấp ạ

Comments ( 1 )

  1. $\begin{array}{l} a + b + c + d = 0\\  \Leftrightarrow a + d =  – \left( {b + c} \right)\\  \Leftrightarrow {\left( {a + d} \right)^3} =  – {\left( {b + c} \right)^3}\\  \Leftrightarrow {a^3} + {d^3} + 3ad\left( {a + d} \right) =  – \left( {{b^3} + {c^3} + 3bc\left( {b + c} \right)} \right)\\  \Leftrightarrow {a^3} + {d^3} + {b^3} + {c^3} =  – 3ad\left( {a + d} \right) – 3bc\left( {b + c} \right)\\  \Leftrightarrow {a^3} + {d^3} + {b^3} + {c^3} =  – 3ad\left( { – \left( {b + c} \right)} \right) – 3bc\left( {b + c} \right)\\  \Leftrightarrow {a^3} + {d^3} + {b^3} + {c^3} = 3ab\left( {b + c} \right) – 3bc\left( {b + c} \right)\\  \Leftrightarrow {a^3} + {b^3} + {c^3} + {d^3} = 3\left( {b + c} \right)\left( {ad – bc} \right) \end{array}$  

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222-9+11+12:2*14+14 = ? ( )