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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x đi các pác ưi :> a) `|x-5/3|<1/3` b) `|x+11/2|>|-5,5|` c) `2/5<|x-7/5|<3/5`

Toán Lớp 7: Tìm x đi các pác ưi :>
a) |x-5/3|<1/3 b) |x+11/2|>|-5,5|
c) 2/5<|x-7/5|<3/5

Comments ( 1 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     |x-5/3| < 1/3
    -1/3<x-5/3<1/3
    -1/3+5/3<x<1/3+5/3
    4/3<x<6/3
    4/3 < x<2
    |x+11/2| > | -5,5|
    |x+11/2|>5,5
    \(\left[ \begin{array}{l}x+\dfrac{11}{2}<5,5\\x+\dfrac{11}{2}>5,5\end{array} \right.\) 
    \(\left[ \begin{array}{l}x<-11\\x>0\end{array} \right.\) 
    $\dfrac{2}{5}<|x-\dfrac{7}{5}|<\dfrac{3}{5}$
    \(\left[ \begin{array}{l}|x-\dfrac{7}{5}|>\dfrac{2}{5}\\|x-\dfrac{7}{5}|< \dfrac3 5\end{array} \right.\)
    \(\left[ \begin{array}{l}\left[ \begin{array}{l}x-\dfrac7 5 <-\dfrac2 5\\x-\dfrac7 5 >\dfrac2 5\end{array} \right.\\\dfrac{-3}{5} <x-\dfrac{7}{5}< \dfrac3 5\end{array} \right.\) 
    \(\left[ \begin{array}{l}\left[ \begin{array}{l}x<1\\x>\dfrac9 5\end{array} \right.\\\dfrac{4}{5} <x< \dfrac{10} 5\end{array} \right.\)
    $-> \dfrac{4}{5}<x<1$

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222-9+11+12:2*14+14 = ? ( )