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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: giải phương trình: a) 2sin(x+15độ)=3 b) sin(4x+1/2)=1/3

Toán Lớp 10: giải phương trình:
a) 2sin(x+15độ)=3
b) sin(4x+1/2)=1/3

Comments ( 2 )

  1. $a)$ 2sin(x+15độ)=3
    $sin(x+15^o)=\dfrac{3}{2}$
    Vì $\dfrac{3}{2}>1$ mà $-1≤sinx≤1$
    $⇒$ Phương trình vô nghiệm
    $b)$sin(4x+1/2)=1/3
    $⇔$\(\left[ \begin{array}{l}4x+\dfrac{1}{2}=arcsin(\dfrac{1}{3})+k2\pi\\4x+\dfrac{1}{2}=\pi-arcsin(\dfrac{1}{3})+k\pi\end{array} \right.\) 
    $⇔$\(\left[ \begin{array}{l}4x=-\dfrac{1}{2}+arcsin(\dfrac{1}{3})+k2\pi\\4x=-\dfrac{1}{2}+\pi-arcsin(\dfrac{1}{3})+k2\pi\end{array} \right.\) 
    $⇔$\(\left[ \begin{array}{l}x=-\dfrac{1}{8}+\dfrac{1}{4}arcsin(\dfrac{1}{3})+\dfrac{k\pi}{2}\\x=-\dfrac{1}{8}+\dfrac{1}{4}\pi-\dfrac{1}{4}arcsin(\dfrac{1}{3})+\dfrac{k\pi}{2}\end{array} \right.\) 

  2. Giải đáp:
     a, 2sin (x +15°) =3
    <=> sin (x +15°)= 3/2
    => phương trình vô nghiệm vì 3/2 \notin [-1;1]
    => S= ∅
    b, sin (4x +1/2) =1/3
    <=>\(\left[ \begin{array}{l}4x +\dfrac12= arcsin \dfrac13 + k2π \\4x +\dfrac12 = π -arcsin \dfrac13 + k2π\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}4x =-\dfrac12 + arcsin \dfrac13 + k2π \\4x  = -\dfrac12 + π -arcsin \dfrac13 + k2π\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x =-\dfrac18 + \dfrac{arcsin \dfrac13}{4} + \dfrac{kπ}{2} \\x = -\dfrac18 + \dfrac{π -arcsin \dfrac13}{4} + \dfrac{kπ}{2}\end{array} \right.\)

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222-9+11+12:2*14+14 = ? ( )

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