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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Chứng minh : ( a – 1) x ( 3 – 2a ) – a( a + 5 ) chia hết cho 3

Toán Lớp 7: Chứng minh : ( a – 1) x ( 3 – 2a ) – a( a + 5 ) chia hết cho 3

Comments ( 2 )

  1. Giải đáp:
    $\\$
    (a-1) (3-2a) – a (a+5)
    = a (3-2a) –  (3-2a) – a^2 – 5a
    = 3a – 2a^2 – 3 + 2a – a^2 – 5a
    = (3a + 2a-5a) + (-2a^2 – a^2) – 3
    = -3a^2 – 3
    = 3 (-a^2 – 1)
    Vì 3 chia hết cho 3
    -> 3 (-a^2-1) chia hết cho 3
    -> (a-1) (3-2a) – a (a+5) chai hết cho 3

  2. Giải:
    (a – 1)(3 – 2a) – a(a + 5)
    = 3a – 3 – 2a^2 + 2a – a^2 – 5a
    = (3a + 2a – 5a) – (2a^2 + a^2) – 3
    = -3a^2 – 3
    = 3(-a^2 – 1) \vdots 3 (đpcm)
     

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222-9+11+12:2*14+14 = ? ( )

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