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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: a+b/a-b=c+a/c-a a^2+c^2/b^2+a^2=c/b cm nha đk a^2=bc

Toán Lớp 7: a+b/a-b=c+a/c-a
a^2+c^2/b^2+a^2=c/b
cm nha đk a^2=bc

Comments ( 2 )

  1. 1)$\frac{a+b}{a-b}$=$\frac{a(a+b)}{a(a-b)}$=$\frac{a²+ab}{a²-ab}$=$\frac{bc+ab}{bc-ab}$=$\frac{b(c+a)}{b(c-a)}$=$\frac{c+a}{c-a}$
    ⇒$\frac{a+b}{a-b}$=$\frac{c+a}{c-a}$
    2)$\frac{a²+c²}{b²+a²}$=$\frac{bc+c²}{bc+b²}$=$\frac{c(b+c)}{b(c+b)}$=$\frac{c}{b}$
    ⇒$\frac{a²+c²}{b²+a²}$=$\frac{c}{b}$
    Xin câu trả lời hay nhất ạ
    #Murad
     

  2. $\frac{a+b}{a-b}$=$\frac{a(a+b)}{a(a-b)}$=$\frac{a²+ab}{a²-ab}$=$\frac{bc+ab}{bc-ab}$=$\frac{b(c+a)}{b(c-a)}$=$\frac{c+a}{c-a}$
    Vậy $\frac{a+b}{a-b}$=$\frac{c+a}{c-a}$
    Đc 1 câu nhá
    Câu 2:
    $\frac{a²+c²}{b²+a²}$=$\frac{bc+c²}{bc+b²}$=$\frac{c(b+c)}{b(c+b)}$=$\frac{c}{b}$
    Vậy $\frac{a²+c²}{b²+a²}$=$\frac{c}{b}$
    Xong 2 câu nhá
     

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222-9+11+12:2*14+14 = ? ( )

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