Toán Lớp 6: Tìm x
|1/1.2+1/2.3+…+1/99.100+x|=-|25-(-50)|
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Toán Lớp 6: Tìm x
|1/1.2+1/2.3+…+1/99.100+x|=-|25-(-50)|
Comments ( 2 )
|1/1.2+1/2.3+…+1/99.100+x|=-|25+50)|
|1/1.2+1/2.3+…+1/99.100+x|=-75
Vì |1/1.2+1/2.3+…+1/99.100+x|\geq0=>|1/1.2+1/2.3+…+1/99.100+x|=-75(vô lí)
Vậy x in cancel{0}
=> |1 – 1/100 + x| = -|25 + 50|