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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 3. Tìm x , biết : a) x mũ 2 – 9 + 5 ( x – 3 ) = 0 b) ( x – 2 ) ( x mũ 2 + 2x + 4 ) – x ( x mũ 2 + 2 ) = 15

Toán Lớp 8: 3. Tìm x , biết :
a) x mũ 2 – 9 + 5 ( x – 3 ) = 0
b) ( x – 2 ) ( x mũ 2 + 2x + 4 ) – x ( x mũ 2 + 2 ) = 15

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    3)
    a)
    x^2 – 9 + 5 ( x – 3 ) = 0
    => ( x – 3 ) ( x + 3 ) + 5 ( x – 3 ) = 0
    => ( x – 3 ) ( x + 3 + 5 ) = 0
    => ( x – 3 ) ( x + 8 ) = 0
    => x – 3 = 0 hoặc x + 8 = 0
    => x = 0 + 3 hoặc x = 0 – 8
    => x = 3 hoặc x = -8
    Vậy x = 3 hoặc x = -8
    b)
    ( x – 2 ) ( x^2 + 2x + 4 ) – x ( x^2 + 2 ) = 15
    => x^3 – 2^3 – x^3 – 2x = 15
    => -8 – 2x = 15
    => -2x = 15 + 8
    => -2x = 23
    => x = 23/(-2)
    => x = (-23)/2
    Vậy x = (-23)/2
     

  2. a)
    x^2 – 9 + 5(x – 3) = 0
    ⇔ (x – 3)(x + 3) + 5(x – 3) = 0
    ⇔ (x – 3)(x + 3 + 5) = 0
    ⇔ (x – 3)(x + 8) = 0
    ⇒ \(\left[ \begin{array}{l}x = 3\\x=-8\end{array} \right.\) 
    Vậy  S = {3 ; -8}
    b)
    (x – 2)(x^2 + 2x + 4) – x(x^2 + 2) = 15
    ⇔ x(x^2 + 2x + 4) – 2(x^2 + 2x + 4) – x^3 – 2x = 15
    ⇔ x^3 + 2x^2 + 4x – 2x^2 – 4x – 8 – x^3 – 2x = 15
    ⇔ -2x = 15 + 8
    ⇔ -2x = 23
    ⇔ x = -23/2
    Vậy  x = -23/2

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222-9+11+12:2*14+14 = ? ( )