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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Khai triển các biểu thức sau: a.(2x-3)^2 b.(3/2-x)^2 c.(2x+3y)^2 d.(a^2-2)^2 e.(2x-y+z)^2

Toán Lớp 8: Khai triển các biểu thức sau:
a.(2x-3)^2
b.(3/2-x)^2
c.(2x+3y)^2
d.(a^2-2)^2
e.(2x-y+z)^2

Comments ( 2 )

  1. a)
    (2x-3)^2
    =  (2x)^2 – 2 . 2x . 3 + 3^2
    = 4x^2 – 12x + 9
    b)
    (3/2 – x)^2
    = (3/2)^2 – 2 . 3/2 . x + x^2
    = 9/4 – 3x + x^2
    c)
    (2x+3y)^2
    = (2x)^2 + 2 . 2x . 3y + (3y)^2
    = 4x^2 + 12xy + 9y^2
    d)
    (a^2 – 2)^2
    = (a^2)^2 – 2 . a^2 . 2 + 2^2
    = a^4 – 4a^2+ 4
    e)
    (2x – y + z)^2
    = [ (2x-y) + z]^2
    = (2x-y)^2 + 2 (2x-y) . z + z^2
    = [ (2x)^2 – 2 . 2x . y + y^2] + 2z (2x-y) + z^2
    = 4x^2 – 4xy + y^2 + 4xz – 2yz + z^2
     

  2. $#Dứa$
    a, (2x – 3)² = (2x)² – 2.2x.3 + 3² = 4x² – 12x + 9
    b, ($\frac{3}{2}$-x)² = ($\frac{3}{2}$)² – 2.$\frac{3}{2}$.x + x² = $\frac{9}{4}$ – 3x + x²
    c, (2x + 3y)² = (2x)² – 2.2x.3y + 3y² = 4x² – 12xy + 9y²
    d, (a² – 2)² = (a²)² – 2.a².a + 2² = $a^{4}$ – 4a² + 4
    e, (2x – y + z)² = [(2x – y) + z]² = (2x – y)² + 2(2x – y) . z + z² = 4x² – 4xy + y² + 4xz – 2xz + z²
    * Sorry mải buôn quá nên quên khum lm bài =v=
     

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222-9+11+12:2*14+14 = ? ( )