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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: BT: Giả các Pt sau a) 3 – 4x(25 – 2x)=8x^2 + x – 300 b) x+2/x-2 – 1/x =2/x(x – 2)

Toán Lớp 9: BT: Giả các Pt sau
a) 3 – 4x(25 – 2x)=8x^2 + x – 300
b) x+2/x-2 – 1/x =2/x(x – 2)

Comments ( 2 )

  1. a)
    <=>34x(252x)=8x^2+x300
    <=>3100x+8x^2=8x^2+x300
    <=>8x^2100x+3=8x^2+x300
    <=>−101x=3003
    <=> x = 3
    b)  $\frac{(x+2)x}{(x-2)x}$- $\frac{x-2}{x(x-2)}$= $\frac{2}{x(x-2)}$ 
    <=> $x^{2}$ +2x -x-2=2
    <=> $x^{2}$ +x4=0
    <=> (x+$\frac{1}{2}$ )^24($\frac{1}{2}$ )^2=0
    <=> x + $\frac{1}{2}$  = + – $\sqrt{\frac{17}{4}}$ 
    <=> x = $\frac{-1+\sqrt{17}}{2}$ 
    <=> x = $\frac{-1-\sqrt{17}}{2}$ 

  2. Giải đáp:
    a) 3 – 4x(25 – 2x)=8x^2 + x – 300
    <=> 3 – 100x + 8x² – 8x^2 – x + 300= 0
    <=> -101x + 303 = 0
    <=> – 101 ( x – 3)= 0
    <=> x= 3
    Vậy S={3}
    b) (x+ 2)/(x-2) – 1/x =2/(x(x – 2))
    ĐKXĐ: x ≠ 0; 2
    <=> (x.(x + 2))/(x(x-2)) – (x-2)/(x(x-2)) = 2/(x(x-2))
    => x^2 + 2x – x + 2 – 2= 0
    <=> x^2 + x = 0
    <=> x(x+1)= 0
    <=>\(\left[ \begin{array}{l}x=0\\x+1=0\end{array} \right.\)
    <=>\(\left[ \begin{array}{l}x=0(KTM)\\x=-1(TM)\end{array} \right.\) 
    Vậy S={ -1}

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222-9+11+12:2*14+14 = ? ( )