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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: ( x + 3/5 ) ( 3/2 – 2x ) = 0 ( -5/4 . x + 1/2 ) [ 3/5 – (-2/3.x)] = 0

Toán Lớp 6: ( x + 3/5 ) ( 3/2 – 2x ) = 0
( -5/4 . x + 1/2 ) [ 3/5 – (-2/3.x)] = 0

Comments ( 2 )

  1. Lời giải:
    1)
    (x+3/5)(3/2-2x)=0
    $⇔\left[\begin{matrix}x+\dfrac{3}{5}=0\\ \dfrac{3}{2}-2x=0\end{matrix}\right.$
    $⇔\left[\begin{matrix}x=\dfrac{-3}{5}\\ -2x=\dfrac{-3}{2}\end{matrix}\right.$
    $⇔\left[\begin{matrix}x=\dfrac{-3}{5}\\ x=\dfrac{3}{4}\end{matrix}\right.$
    Vậy x∈{-3/5;3/4}
    2)
    (-5/4.x+1/2)[3/5-(-2/3.x)]=0
    ⇔(-5/4.x+1/2)(3/5+2/3x)=0
    $⇔\left[\begin{matrix}\dfrac{-5}{4}x+\dfrac{1}{2}=0\\ \dfrac{3}{5}+\dfrac{2}{3}x=0\end{matrix}\right.$
    $⇔\left[\begin{matrix}\dfrac{-5}{4}x=\dfrac{-1}{2}\\ \dfrac{2}{3}x=\dfrac{-3}{5}\end{matrix}\right.$
    $⇔\left[\begin{matrix}x=\dfrac{2}{5}\\ x=\dfrac{-9}{10}\end{matrix}\right.$
    Vậy x∈{2/5;-9/10}

  2. Giải đáp+Lời giải và giải thích chi tiết:
    (x+3/5)(3/2-2x)=0
    =>[(x+3/5=0),(3/2-2x=0):}
    =>[(x=-3/5),(2x=3/2):}
    =>[(x=-3/5),(x=3/4):}
    Vậy x=-3/5 hoặc x=3/4.
    (-5/4x+1/2)[3/5-(-2/3x)]=0
    =>(-5/4x+1/2)(2/3x+3/5)=0
    =>[(-5/4x+1/2=0),(2/3x+3/5=0):}
    =>[(-5/4x=-1/2),(2/3x=-3/5):}
    =>[(x=2/5),(x=-9/10):}
    Vậy x=2/5 hoặc x=-9/10.

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222-9+11+12:2*14+14 = ? ( )

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