Toán Lớp 8: (x^2+2xy+y^2):(x+y)=
(2x^5-4x^3+3x^2):2x^2=
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Toán Lớp 8: (x^2+2xy+y^2):(x+y)=
(2x^5-4x^3+3x^2):2x^2=
Comments ( 2 )
Giải đáp:
(x^2+2xy+y^2):(x+y)
= ( x^2 + 2.x.y + y^2) : ( x + y)
= ( x + y)^2 : ( x + y)
= ( x + y)
$\\$
(2x^5-4x^3+3x^2):2x^2
= ( 2x^5 : 2x^2) – ( 4x^3 : 2x^2) + ( 3x^2 : 2x^2)
= x^3 – 2x + 3/2
Áp dụng: ( A + B)^2 = A^2 + 2AB + B^2
( x^2 + 2xy + y^2 ) : ( x + y )
= ( x + y )^2 : ( x + y )
= x + y
————–
( 2x^5 – 4x^3 + 3x^2 ) : 2x^2
= 2x^5 : 2x^2 – 4x^3 : 2x^2+3x^2 : 2x^2
= x^3 – 2x + 3/2