Toán Lớp 7: 4 mũ 3x+1+8 mũ 2x+1 = 12 * 2 mũ 2016

Question

Toán Lớp 7:  4 mũ 3x+1+8 mũ 2x+1 = 12 * 2 mũ 2016

minhtamnguyet88 · Answer

$  $   4^{3x+1} + 8^{2x+1} = 12 . 2^{2016}   -> (2^2)^{3x+1} + (2^3)^{2x+1} = 2^2 . 2^{2016} . 3   -> 2^{2 (3x+1)} + 2^{3 (2x+1)} = 2^{2018} . 3   -> 2^{6x + 2} + 2^{6x + 3} = 2^{2018} . 3   -> 2^{6x} . 2^2 + 2^{6x} . 2^3 = 2^{2018} . 3   -> 2^{6x} . (4 + 8) = 2^{2018} . 3   -> 2^{6x} . 12 = 2^{2018}.3   ->2^{6x} . 2^2 . 3 = 2^{2018} . 3   ->2^{6x+2} = 2^{2018} . 3 : 3   ->2^{6x+2}=2^{2018}   -> 6x+2=2018   ->6x=2018 - 2   ->6x=2016   ->x=2016 : 6   ->x=336   Vậy x=336

hiennhi98 · Answer

Giải đáp+Lời giải và giải thích chi tiết:    4^3x+1  +  8^2x+1 = 12 . 2^2016    (2^2)^(3x+1)+ (2^3)^(2x+1) = 12.2^2016    2^(6x+2)+ 2^(6x+3) = 2^2 . 3.2^2016    2^(6x+2)+ 2. 2^(6x+2) = 3.2^2018    3. 2^(6x+2) = 3.2^2018    2^(6x+2) = 2^2018   6x + 2 = 2018   6x = 2018 - 2   6x = 2016   x = 2016 : 6   x =  336   $@chienbinhkieuhanh$