Toán Lớp 8: Tìm x biết: (2x+1)^2-(3-2x)^ 2+4=0
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Toán Lớp 8: Tìm x biết: (2x+1)^2-(3-2x)^ 2+4=0
Comments ( 2 )
$⇔4x^2+4x+1-(9-12x+4x^2)+4=0$
$⇔4x^2+4x+1-9+12x-4x^2+4=0$
$⇔16x-4=0$
$⇔16x=4$
$⇔x=\dfrac{1}{4}$
Vậy S={\frac{1}{4}}