Toán Lớp 6: tìm số nguyên x sao cho :
4x + 3 chia hết cho x – 2
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Toán Lớp 6: tìm số nguyên x sao cho :
4x + 3 chia hết cho x – 2
Comments ( 2 )
Giải đáp:
4x + 3 \vdots x – 2
↔ 4x – 8 + 11 \vdots x – 2
↔ 4.(x – 2) + 11 \vdots x – 2
↔ 11 \vdots x – 2
↔ x – 2 ∈ Ư_{(11)} = {1;-1;11;-11}
↔ x ∈ {3;1; 13; -9}
Vậy x ∈ {3;1; 13; -9}
$#dariana$
4x+3\vdotsx-2
<=>4x-8+11vdotsx-2
<=>4(x-2)+11\vdotsx-2
<=>11\vdotsx-2
<=>x-2\inƯ(11)={-1;1;-11;11}
->x-2=1->x=3
->x-2=-1->x=1
->x-2=11->x=13
->x-2=-11->x=-9
Vậy x\in{3;1;13;-9}