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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tính theo 2 cách ( / phần ): (4-1/2+2/3)-(5+3/2-6/5)-(7-7/3-45/5)

Tháng Mười Một 1, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: Tính theo 2 cách ( / phần ): (4-1/2+2/3)-(5+3/2-6/5)-(7-7/3-45/5)

Comments ( 2 )

  1. truongthanhhung
    truongthanhhung
    1 Tháng Mười Một, 2022 at 7:59 sáng
    Reply
    Cách 1 :
    ( 4 – 1/2 + 2/3) – ( 5 + 3/2 – 6/5) – ( 7 – 7/3 – 45/5)
    = ( 24/6 – 3/6 + 4/6) – ( 50/10 + 15/10 – 12/10) – ( 21/3 – 7/3 – 9)
    = 25/6 – 53/10 – (-13/3)
    = 16/5
    Cách 2 :
    ( 4 – 1/2 + 2/3) – ( 5 + 3/2 – 6/5) – ( 7 – 7/3 – 45/5)
    = 4 – 1/2 + 2/3 – 5 – 3/2 + 6/5 – 7 + 7/3 + 45/5
    = ( 4 – 5  – 7) – ( 1/2 + 3/2) + ( 6/5 + 45/5) + ( 2/3 + 7/3)
    = -8 – 2 + 51/5 + 9/3
    = -10 + 51/3 + 3
    =(-10 + 3) + 51/3
    = -7 + 51/3
    = -35/5 + 51/3
    = 16/5
     

  2. cattien
    cattien
    1 Tháng Mười Một, 2022 at 7:58 sáng
    Reply
    Lời giải và giải thích chi tiết:
    (4 – 1/2 + 2/3) – (5 + 3/2 – 6/5) – (7 – 7/3 – 45/5)
    = 4 – 1/2 + 2/3 – 5 – 3/2 + 6/5 – 7 + 7/3 + 9
    = 4 – 5 – 7 + 9 – 1/2 – 3/2 + 2/3 + 7/3 + 6/5
    = 1 – 2 + 3 + 6/5
    = 2 + 6/5
    = 16/5
    (4 – 1/2 + 2/3) – (5 + 3/2 – 6/5) – (7 – 7/3 – 45/5)
    = (24/6 – 3/6 + 4/6) – (50/10 + 15/10 – 12/10)  – (-6/3 – 7/3)
    = 25/6 – 53/10 + 13/3
    = 25/6 + 13/3 – 53/10
    = 51/6 – 53/10
    = 510/60 – 318/60
    = 192/60
    = 16/5

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222-9+11+12:2*14+14 = ? ( )

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