Toán Lớp 8: tính
x+3/x^2-4 nhân 8-12x+6x^2-x^3/9x +27
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Toán Lớp 8: tính
x+3/x^2-4 nhân 8-12x+6x^2-x^3/9x +27
Comments ( 2 )
\dfrac{{x + 3}}{{{x^2} – 4}}.\dfrac{{8 – 12x + 6{x^2} – {x^3}}}{{9x + 27}}\\
= \dfrac{{x + 3}}{{\left( {x – 2} \right)\left( {x + 2} \right)}}.\dfrac{{{{\left( {2 – x} \right)}^3}}}{{9\left( {x + 3} \right)}}\\
= \dfrac{{ – {{\left( {2 – x} \right)}^2}}}{{\left( {x + 2} \right).9}}\\
= \dfrac{{ – 4 + 4x – {x^2}}}{{9x + 18}}
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