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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: b, (x^4+x^3-6x^2-5x+5):(x^2+x-1)

Toán Lớp 8: b, (x^4+x^3-6x^2-5x+5):(x^2+x-1)

Comments ( 2 )

  1. Hướng dẫn trả lời:
    b) (x^4 + x^3 – 6x^2 – 5x + 5) ÷ (x^2 + x – 1)
    = (x^4 + x^3 – x^2 – 5x^2 – 5x + 5) ÷ (x^2 + x – 1)
    = [(x^4 + x^3 – x^2) – (5x^2 + 5x – 5)] ÷ (x^2 + x – 1)
    = [x^2*(x^2 + x – 1) – 5*(x^2 + x – 1)] ÷ (x^2 + x – 1)
    = (x^2 – 5)*(x^2 + x – 1) ÷ (x^2 + x – 1)
    = x^2 – 5
    Giải đáp:
    (x^4 + x^3 – 6x^2 – 5x + 5) ÷ (x^2 + x – 1) = x^2 – 5

  2. Giải đáp:
    x^2-5
    Lời giải và giải thích chi tiết:
    b) (x^4+x^3-6x^2-5x+5):(x^2+x-1)
    =(x^4+x^3-x^2-5x^2-5x+5):(x^2+x-1)
    =[(x^4+x^3-x^2)-(5x^2+5x-5)]:(x^2+x-1)
    =[x^2(x^2+x-1)-5(x^2+x-1)]:(x^2+x-1)
    =[(x^2+x-1)(x^2-5)]:(x^2+x-1)
    =x^2-5

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222-9+11+12:2*14+14 = ? ( )