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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: Mọi người giúp e với!! Em cần gấp lắm ạ 1) sinx = -sin9x 2) sinx = sin(π-3x) 3) sin(-5x) = -sin2x

Tháng Mười 22, 2022 Toán học 1 Comment 0 views

Toán Lớp 11: Mọi người giúp e với!! Em cần gấp lắm ạ
1) sinx = -sin9x
2) sinx = sin(π-3x)
3) sin(-5x) = -sin2x

Comments ( 1 )

  1. diemmyhoa
    diemmyhoa
    22 Tháng Mười, 2022 at 4:32 chiều
    Reply
    $1)sinx=-sin9x$
    $⇔sinx=sin(-9x)$
    $⇔$\(\left[ \begin{array}{l}x=-9x+k2\pi\\x=\pi+9x+k2\pi\end{array} \right.\) 
    $⇔$\(\left[ \begin{array}{l}x=\dfrac{k\pi}{5}\\x=\dfrac{-\pi}{8}-\dfrac{k\pi}{4}\end{array} \right.\) 
    $2)sinx=sin(\pi-3x)$
    $⇔$\(\left[ \begin{array}{l}x=\pi-3x+k2\pi\\x=\pi-\pi+3x+k2\pi\end{array} \right.\)
    $⇔$ \(\left[ \begin{array}{l}4x=\pi+k2\pi\\-2x=k2\pi\end{array} \right.\)
    $⇔$\(\left[ \begin{array}{l}x=\dfrac{\pi}{4}+\dfrac{k\pi}{2}\\x=-k\pi\end{array} \right.\)
    $3)sin(-5x)=-sin2x$
    $⇔sin(-5x)=sin(-2x)$
    $⇔$\(\left[ \begin{array}{l}-5x=-2x+k2\pi\\-5x=\pi+2x+k2\pi\end{array} \right.\) 
    $⇔$\(\left[ \begin{array}{l}-3x=k2\pi\\-7x=\pi+k2\pi\end{array} \right.\) 
    $⇔$\(\left[ \begin{array}{l}x=\dfrac{-k2\pi}{3}\\x=\dfrac{-\pi}{7}-\dfrac{k2\pi}{7}\end{array} \right.\) 

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222-9+11+12:2*14+14 = ? ( )

Cẩm Thúy

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