Toán Lớp 9: $x^{2}$ $-2x \leq 0$
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Toán Lớp 9: $x^{2}$ $-2x \leq 0$
Giải bất phương trình
Comments ( 2 )
{x^2} – 2x \le 0\\
\to x\left( {x – 2} \right) \le 0\\
\to \left[ \begin{array}{l}
\left\{ \begin{array}{l}
x \le 0\\
x – 2 \ge 0
\end{array} \right.\\
\left\{ \begin{array}{l}
x \ge 0\\
x – 2 \le 0
\end{array} \right.
\end{array} \right.\\
\to \left[ \begin{array}{l}
\left\{ \begin{array}{l}
x \le 0\\
x \ge 2
\end{array} \right.\left( l \right)\\
\left\{ \begin{array}{l}
x \ge 0\\
x \le 2
\end{array} \right.
\end{array} \right.\\
\to 2 \ge x \ge 0
\end{array}\)