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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tính x (4x+3)(4x-3)-(4x-5) mũ 2= 46 giúp mik vs mn

Toán Lớp 8: tính x
(4x+3)(4x-3)-(4x-5) mũ 2= 46
giúp mik vs mn

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
      (4x+3)(4x-3) – (4x-5)^2 =  46
    -> (4x)^2 – 3^2 – [(4x)^2 – 2.4x.5 + 5^2] = 46
    -> 16x^2 – 9 – (16x^2 – 40x + 25) = 46
    -> 16x^2 – 9 – 16x^2 + 40x – 25 = 46
    -> 40x – 34 = 46
    -> 40x = 46 + 34 = 80
    -> x= 80:40 = 2
    Vậy x=2

  2. Giải đáp:
    $\begin{array}{l}(4x+3)(4x-3)-(4x-5)^2-46\\\leftrightarrow 16x^2-9-(16^2-40x+25)=46\\\leftrightarrow 16x^2-9-16x^2+40x-25=46\\\leftrightarrow -34+40x=46\\\leftrightarrow 40x=80\\\leftrightarrow x=2\\\text{Vậy} \ S=\{2\}\end{array}$

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222-9+11+12:2*14+14 = ? ( )