Toán Lớp 8: Tìm X bt;
f/ x(2x-3)-6+4x=0
giúp!!!!!!!!!!!!!
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Toán Lớp 8: Tìm X bt;
f/ x(2x-3)-6+4x=0
giúp!!!!!!!!!!!!!
Comments ( 2 )
Giải đáp:
x(2x-3)-6+4x=0
= 2×2+x-6=0
=(x+2)(2x-3)=0
x+2=0
2x-3=0
x=-2
x=3/2
x(2x-3)-6+4x=0
x(2x-3)+(4x-6)=0
x(2x-3)+2(2x-3)=0
(x+2)(2x-3)=0
=> $\left[\begin{matrix} x+2=0\\ 2x-3=0\end{matrix}\right.$
=> $\left[\begin{matrix} x=-2\\ 2x=3\end{matrix}\right.$
=> $\left[\begin{matrix} x=-2\\ x=\dfrac{3}{2}\end{matrix}\right.$