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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: `\frac{\sqrt{11}}{\sqrt{22}}+\frac{\sqrt{45}}{3}+\sqrt{3-2\sqrt{2}}+(1+\sqrt{5})^2` Rút gọn

Home/ Toán Lớp 9: `\frac{\sqrt{11}}{\sqrt{22}}+\frac{\sqrt{45}}{3}+\sqrt{3-2\sqrt{2}}+(1+\sqrt{5})^2` Rút gọn

Toán Lớp 9: `\frac{\sqrt{11}}{\sqrt{22}}+\frac{\sqrt{45}}{3}+\sqrt{3-2\sqrt{2}}+(1+\sqrt{5})^2` Rút gọn

Tháng Chín 3, 2022 Toán học 2 Comments 0 views

Toán Lớp 9: \frac{\sqrt{11}}{\sqrt{22}}+\frac{\sqrt{45}}{3}+\sqrt{3-2\sqrt{2}}+(1+\sqrt{5})^2
Rút gọn

Comments ( 2 )

  1. ankim
    ankim
    3 Tháng Chín, 2022 at 10:37 chiều
    Reply
    \frac{\sqrt{11}}{\sqrt{22}}+\frac{\sqrt{45}}{3}+\sqrt{3-2\sqrt{2}}+(1+\sqrt{5})^2
    =\sqrt{\frac{11}{22}}+\frac{3\sqrt{5}}{3}+\sqrt{(\sqrt{2}-1)^2}+1+5+2\sqrt{5}
    =\frac{1}{\sqrt{2}}+\sqrt{5}+\sqrt{2}-1+6+2\sqrt{5}
    =\frac{1+3\sqrt{10}+2+5\sqrt{2}}{\sqrt{2}}
    =\frac{3+3\sqrt{10}+5\sqrt{2}}{\sqrt{2}}
    =\frac{3\sqrt{2}+6\sqrt{5}+10}{2}

  2. thanoanghha
    thanoanghha
    3 Tháng Chín, 2022 at 10:37 chiều
    Reply
    \sqrt{11}/\sqrt{22}+\sqrt{45}/3+\sqrt{3-2\sqrt{2}}+(1+\sqrt{5})^2
    =\sqrt{11}/(\sqrt{11}.\sqrt{2})+(3\sqrt{5})/3+\sqrt{(\sqrt{2})^2-2.\sqrt{2}.1+1^2}+(1+2\sqrt{5}+5)
    =1/\sqrt{2}+\sqrt{5}+\sqrt{(\sqrt{2}-1)^2}+(6+2\sqrt{5})
    =1/\sqrt{2}+\sqrt{5}+(\sqrt{2}-1)+6+2\sqrt{5}
    =1/\sqrt{2}+\sqrt{5}+\sqrt{2}-1+6+2\sqrt{5}
    =1/\sqrt{2}+3\sqrt{5}+\sqrt{2}+5
    =(1+3\sqrt{10}+2+5\sqrt{2})/\sqrt{2}
    =(3+3\sqrt{10}+5\sqrt{2})/\sqrt{2}
    =(\sqrt{2}(3+3\sqrt{10}+5\sqrt{2}))/(\sqrt{2}.\sqrt{2})
    =(3\sqrt{2}+6\sqrt{5}+10)/2

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222-9+11+12:2*14+14 = ? ( )

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