Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giúp mk vs ạ: d. ( x – 3 )( x + 3 ) – ( 2 – x )( -x ) = -17 e. ( 3x + 1 )^2 – ( 2x – 3 )^2 = 5(x + 2)( x – 2 )

Toán Lớp 8: Giúp mk vs ạ:
d. ( x – 3 )( x + 3 ) – ( 2 – x )( -x ) = -17
e. ( 3x + 1 )^2 – ( 2x – 3 )^2 = 5(x + 2)( x – 2 )

Comments ( 2 )

  1. a,(x-3)(x+3)-(2-x)(-x)=-17
       =x^2-9 -(-2x+x^2)=-17
       =x^2-9+2x-x^2=-17
       =-9+2x=-17
       =-9+2x+17=0
       =8+2x=0
       =2x=0-8
       =2x=-8
       =x=-4
     b.( 3x + 1 )^2 – ( 2x – 3 )^2 = 5(x + 2)( x – 2 )
    =(3x^2)+2.3x.1+1^2-(2x)^2-2.2x.3+3^2=5.(x^2-2^2)
     =9x^2+6x+1-4x^2-12x+9=5x^2-20
     =9x^2+6x+1-4x^2-12x+9-5x^2+20=0
     =-6x+30=0
     =-6x=-30
      =x=5

  2. Giải đáp + Lời giải và giải thích chi tiết !
    d)
    (x-3)(x+3)-(2-x)(-x) = -17
    <=> x^2-9+2x-x^2 = -17
    <=> (x^2-x^2)+2x-9 = -17
    <=> 2x = -8
    <=> x = -4
    Vậy S= {-4}
    e)
    (3x+1)^2-(2x-3)^2 = 5(x-2)(x+2)
    <=> 9x^2+6x+1-4x^2+12x-9 = 5(x^2-4)
    <=> (9x^2-4x^2)+(6x+12x)+(1-9) = 5x^2-20
    <=> 5x^2+18x-8-5x^2+20 = 0
    <=> (5x^2-5x^2)+18x+(-8+20) = 0
    <=> 18x+12 = 0
    <=> 18x = -12
    <=> x = -(2)/3
    Vậy S= {-(2)/3}
     

Leave a reply

222-9+11+12:2*14+14 = ? ( )