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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: sinx.cos2x=sin2x.cos3x-1/2sin5x

Home/ Toán Lớp 11: sinx.cos2x=sin2x.cos3x-1/2sin5x

Toán Lớp 11: sinx.cos2x=sin2x.cos3x-1/2sin5x

Tháng Tám 31, 2022 Toán học 1 Comment 0 views

Toán Lớp 11: sinx.cos2x=sin2x.cos3x-1/2sin5x

Comments ( 1 )

  1. lanhuongthu
    lanhuongthu
    31 Tháng Tám, 2022 at 7:00 sáng
    Reply
    $sinx.cos2x=sin2x.cos3x-\frac{1}{2}sin5x$
    ⇔$\frac{1}{2}(sinx + sin3x) = \frac{1}{2}(sinx + sin5x) – \frac{1}{2}sin5x$
    ⇔$\frac{1}{2}sin3x = 0$
    ⇔$sin3x = 0$
    ⇔$3x = kπ$
    ⇔$x = k\frac{π}{3}$

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222-9+11+12:2*14+14 = ? ( )

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