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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm x: x^2 (x + 1) – x (x + 1) + x (x – 1)

Tháng Tám 26, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: tìm x: x^2 (x + 1) – x (x + 1) + x (x – 1)

Comments ( 2 )

  1. catlantuong
    catlantuong
    26 Tháng Tám, 2022 at 11:27 chiều
    Reply
    ***/
    x^2 (x + 1) – x (x + 1) + x (x – 1)=0
    <=>(x + 1) (x^2- x ) + (x^2 – x)=0
    <=> (x^2- x )(x+1+1)=0
    <=> x(x- 1 )(x+2)=0
    <=>\(\left[ \begin{array}{l}x=0\\x=1\\x=-2\end{array} \right.\)
    Vậy S={-2;0;1}

  2. hienchaudiem
    hienchaudiem
    26 Tháng Tám, 2022 at 11:26 chiều
    Reply
    #tnvt
    x^2(x+1)-x(x+1)+x(x-1)=0
    <=>(x+1)(x^2-x)+x(x-1)=0
    <=>x(x+1)(x-1)+x(x-1)=0
    <=>x(x-1)(x+1+1)=0
    <=>x(x-1)(x+2)=0
    <=>[(x=0),(x-1=0),(x+2=0):}
    <=>[(x=0),(x=1),(x=-2):}
    Vậy x\in{-2;1;0}

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222-9+11+12:2*14+14 = ? ( )

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