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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: tìm giá trị để P=3x-1/2x+2 nguyên

Toán Lớp 8: tìm giá trị để P=3x-1/2x+2 nguyên

Comments ( 1 )

  1. Để P in Z thì:
    (3x – 1) \vdots (2x + 2)    (ĐK: x ne -1)
    => (6x – 2) \vdots (2x + 2)
    => (6x + 6 – 8) \vdots (2x + 2)
    Vì (6x + 6) \vdots (2x + 2)
    => -8 \vdots (2x + 2)
    => (2x + 2) in Ư(-8) = {±1 ; ±2 ; ±4 ; ±8}
    $\begin{array}{|c|c|c|}\hline 2x+2&-8&-4&-2&-1&1&2&4&8\\\hline 2x&-10&-6&-4&-3&-1&0&2&6\\\hline x&-5&-3&-2&-\frac{3}{2}&-\frac{1}{2}&0&1&3\\\hline &tm&tm&tm&tm&tm&tm&tm&tm\\\hline \end{array}$
    Vậy x in {-5 ; -3 ; -2 ; -3/2 ; -1/2 ; 0 ; 1 ; 3} thì P in Z

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222-9+11+12:2*14+14 = ? ( )

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