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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: 1. Tìm x , biết: |x + 3/3 | – 1/3 = 0

Home/ Toán Lớp 7: 1. Tìm x , biết: |x + 3/3 | – 1/3 = 0

Toán Lớp 7: 1. Tìm x , biết: |x + 3/3 | – 1/3 = 0

Tháng Tám 22, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: 1. Tìm x , biết:
|x + 3/3 | – 1/3 = 0

Comments ( 2 )

  1. tuyethutanhthu
    tuyethutanhthu
    22 Tháng Tám, 2022 at 4:16 sáng
    Reply
    | x +$\frac{3}{3}$ | – 1/3 = 0
    | x + $\frac{3}{3}$ | = 0 + $\frac{1}{3}$
    | x + 3/3 | = 1/3
    Vì |1/3| = |-1/3| = 1/3
    => x + 3/3 = 1/3 hoặc x + 3/3 = -1/3
    TH1 : x + 3/3 = 1/3
    x = 1/3 – 3/3
    x =  -2/3
    TH2 : x + 3/3 = -1/3
    x = -1/3 – 3/3
    x = -4/3
    Vậy x ∈ [ -2/3 ; -4/3]
     

  2. thanhtung
    thanhtung
    22 Tháng Tám, 2022 at 4:15 sáng
    Reply
    |x + $\dfrac{3}{3}$ | – $\dfrac{1}{3}$ = 0
                    |x + $\dfrac{3}{3}$ |          = 0 + $\dfrac{1}{3}$
                    |x + $\dfrac{3}{3}$ |          =  $\dfrac{1}{3}$
    ⇒\(\left[ \begin{array}{l}x+\dfrac{3}{3}\ =\dfrac{1}{3}\\x+\dfrac{3}{3}\ = \dfrac{-1}{3}\ \end{array} \right.\) 
    ⇒\(\left[ \begin{array}{l}x=\dfrac{1}{3}\ – \dfrac{3}{3}\ \\x= \dfrac{-1}{3}-\dfrac{3}{3}\ \end{array} \right.\) 
    ⇒\(\left[ \begin{array}{l}x=\dfrac{-2}{3}\ \\x= \dfrac{-4}{3}\ \end{array} \right.\)
    Vậy x= \(\left[ \begin{array}{l}x=\dfrac{-2}{3}\ \\x= \dfrac{-4}{3}\ \end{array} \right.\)

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222-9+11+12:2*14+14 = ? ( )

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