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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn các biểu thức sau: a) (a + b) ² – (a – b) ² b) (a + b)³ – (a – b)3 – 2b³ c) (x + y + z) ² – 2(x + y + z)(x + y) + (x + y)

Toán Lớp 8: Rút gọn các biểu thức sau:
a) (a + b) ² – (a – b) ²

b) (a + b)³ – (a – b)3 – 2b³
c) (x + y + z) ² – 2(x + y + z)(x + y) + (x + y)

Comments ( 2 )

  1. #tnvt
    a)(a+b)^2-(a-b)^2
    =a^2+2ab+b^2-a^2+2ab-b^2
    =4ab
    b)(a+b)^3-(a-b)^3-2b^3
    =a^3+3a^2b+3ab^2+b^3-a^3+3a^2b-3ab^2+b^3-2b^3
    =(a^3-b^3)+(3a^2+3a^2b)+(3ab^2-3ab^2)+b^3+b^3-2b^3
    =6a^2b
    c)(x+y+z)^2-2.(x+y+z).(x+y)+(x+y)^2(Sửa)
    =(x+y+z-x-y)^2
    =z^2
     

  2. Giải đáp+Lời giải và giải thích chi tiết:
    a) (a+b)^2 – (a-b)^2
    = a^2 + 2ab + b^2 – (a^2 – 2ab + b^2)
    = a^2 + 2ab + b^2 – a^2 + 2ab – b^2
    = (a^2 – a^2) + (2ab + 2ab) + (b^2 – b^2)
    = 0 + 4ab + 0
    = 4ab
    b) (a+b)^3 – (a-b)^3 – 2b^3
    = a^3 + 3a^2b + 3ab^2 + b^3 – (a^3 – 3a^2b + 3ab^2 – b^3) – 2b^3
    = a^3 + 3a^2b + 3ab^2 + b^3 – a^3 + 3a^2b – 3ab^2 + b^3 – 2b^3
    = (a^3 – a^3) + (3a^2b + 3a^2b) + (3ab^2 – 3ab^2) + (b^3 + b^3 – 2b^3)
    = 0 + 6a^2b + 0 + 0
    = 6a^2b
    c) (x + y + z)^2 – 2(x + y + z)(x + y) + (x + y)^2
    = (x+y+z-x-y)^2
    = [(x-x)+(y-y)+z]^2
    = z^2

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222-9+11+12:2*14+14 = ? ( )