Toán Lớp 6: Tìm số tự nhiên x biết rằng : { x mũ 2 – [6 mũ 2 – (8 mũ – 9 . 7) mũ 3 – 7 . 5] mũ – 5 . 3} mũ 3 = 1
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Toán Lớp 6: Tìm số tự nhiên x biết rằng : { x mũ 2 – [6 mũ 2 – (8 mũ – 9 . 7) mũ 3 – 7 . 5] mũ – 5 . 3} mũ 3 = 1
Comments ( 1 )
{x^2} – {\left\{ {{{\left[ {{6^2} – {{\left( {{8^2} – 9.7} \right)}^3} – 7.5} \right]}^{ – 5}}.3} \right\}^3} = 1\\
\Leftrightarrow {x^2} – {\left\{ {{{\left[ {36 – {{\left( {64 – 63} \right)}^3} – 35} \right]}^{ – 5}}.3} \right\}^3} = 1\\
\Leftrightarrow {x^2} – {\left[ {{{\left( {1 – {1^3}} \right)}^{ – 5}}.3} \right]^3} = 1\\
\Leftrightarrow {x^2} – {\left( {{0^{ – 5}}.3} \right)^3} = 1\\
\Leftrightarrow {x^2} – {0^3} = 1\\
\Leftrightarrow {x^2} = 1\\
\Leftrightarrow x = 1;x = – 1\\
Vậy\,x = 1;x = – 1
\end{array}$