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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a(b+c)^2(b-c)+b(c+a)^2(c-a)+c(a+b)^2(a-b)

Toán Lớp 8: a(b+c)^2(b-c)+b(c+a)^2(c-a)+c(a+b)^2(a-b)

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    a(b+c)^2(b-c)+b(c+a)^2(c-a)+c(a+b)^2(a-b)
    =a(b+c)(b^2c^2)+b(c+a)(c^2a^2)+c(a+b)(a^2b^2)
    =(ab+ac)(b^2c^2)+(bc+ba)(c^2a^2)+(ca+cb)(a^2b^2)
    =ab^3abc^2+ab^2cac^3+bc^3a^2bc+abc^2a^3b+a^3cab^2c+a^2bcb^3c
    =(b-a)(c-a)(c-b)(c+b+a)

  2. $a$ $(b+c)^{2}$ $(b-c)$$+b$$(c+a)^{2}$ $(c-a)$$+c$$(a+b)^{2}$ $(a-b)$
    =$(ab-ac)$$(b^{2}$ $+2bc$$+c^{2} )$$+$$(bc-ab)$$(c^{2}$$+2ac $$+a^{2} )$$+$$(ac-bc)$$(a^{2}$ +$2ab$$+b^{2})$ 
    =$ab^{3}$ +$2ab^{2}c$ $+abc^{2}$ $-ab^{2}c$ $-2abc^{2}$ $-ac^{3}$ $+bc^{3}$ $+2abc^{2}$ $+a^{2}bc$ $-abc^{2}$ $-2a^{2}bc$ $-a^{3}b$ $+a^{3}c$ $+2a^{2}bc$ $+ab^{2}c$ $-a^{2}bc$ $-2ab^{2}c$ $-b^{3}c$ 
    =$ab^{3}$ $-ac^{3}$ $+bc^{3}$ $-a^{3}b$ $+a^{3}c$ $-b^{3}c$ 
    #doaminhphuc2008
    Chúc bạn học tốt!
    Bạn cho mik xin hay nhất cho nhóm nhé!

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222-9+11+12:2*14+14 = ? ( )