Toán Lớp 11: giúp e giải câu này vs ạ
cos( $/pi$ sinx) = 1
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Toán Lớp 11: giúp e giải câu này vs ạ
cos( $/pi$ sinx) = 1
Comments ( 2 )
x = \dfrac{\pi }{2} + k2\pi \\
x = – \dfrac{\pi }{2} + k2\pi
\end{array} \right.\)
\cos \left( {\pi .\sin x} \right) = – 1\\
\to \left[ \begin{array}{l}
\pi .\sin x = \pi + k2\pi \\
\pi .\sin x = – \pi + k2\pi
\end{array} \right.\\
\to \left[ \begin{array}{l}
\sin x = 1 + k\pi \\
\sin x = – 1 + k\pi
\end{array} \right.\left( {k \in Z} \right)\\
Xét:k = 0\\
\to \left[ \begin{array}{l}
\sin x = 1\\
\sin x = – 1
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{\pi }{2} + k2\pi \\
x = – \dfrac{\pi }{2} + k2\pi
\end{array} \right.\left( {k \in Z} \right)
\end{array}\)