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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: (5x -6).(1999ᒾ + 2 .1999 +1 ) = ( 4.10)

Home/ Toán Lớp 10: (5x -6).(1999ᒾ + 2 .1999 +1 ) = ( 4.10)

Toán Lớp 10: (5x -6).(1999ᒾ + 2 .1999 +1 ) = ( 4.10)

Tháng Bảy 29, 2022 Toán học 2 Comments 0 views

Toán Lớp 10: (5x -6).(1999ᒾ + 2 .1999 +1 ) = ( 4.10)

Comments ( 2 )

  1. khanhngantoan
    khanhngantoan
    29 Tháng Bảy, 2022 at 8:58 chiều
    Reply
    (5x-6).(1999^2+2+999+1)=(4.10^3)^2
    (5x-6).(1999^2+1002)=(4.1000)^2
    (5x-6).(1999^2+1002)=4000^2
    (5x-6).(1999^2+1002)=16000000
    (5x-6).(3996001+1002)=16000000
    (5x-6).3997003=16000000
    (5x-6)=16000000:3997003=12002997
    5x=12002997+6
    5x=12003003
    CHÚC BẠN HỌC TỐT

  2. mytamhoang
    mytamhoang
    29 Tháng Bảy, 2022 at 8:57 chiều
    Reply
    (5x-6)(1999^2+2.1999+1)=4.10
     ⇔(5x-6)(1999+1)^2=40
    ⇔(5x-6)(2000^2)=40
    ⇔(5x-6).4000000=40
    ⇔5x-6=1/100000
    ⇔5x=6,00001
    ⇔x=1,200002

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222-9+11+12:2*14+14 = ? ( )

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