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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: TÌM X (3x-5)(5-3x)+9(x+1)^2=30 (x+4)^2-(x+1)(x-1)=16

Toán Lớp 7: TÌM X
(3x-5)(5-3x)+9(x+1)^2=30
(x+4)^2-(x+1)(x-1)=16

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    a) $(3x-5)(5-3x)+9(x+1)^2=30^{}$
    $15x-9x^2-25+15x+9(x^2+2x+1)-30=0{}$
    $30x-9x^2-25+9x^2+18x+9-30=0^{}$
    $48x-46=0^{}$
    $x= ^{}$ $\frac{23}{24}$
    b) $(x+4)^2-(x+1)(x-1)=16{}$ 
    $(x^2+8x+16)-(x^2-1)=16^{}$
    $x^2+8x+16-x^2+1=16^{}$
    $8x+17=16^{}$
    $8x=-1^{}$
    $x = {}$ $\frac{-1}{8}$
     

  2. (3x-5) (5-3x) + 9 (x+1)^2 = 30
    ⇔ 30x – 9x^2 – 25 + 9 (x^2+2x+1) = 30
    ⇔ 30x – 9x^2 – 25 + 9x^2 + 18x + 9 = 30
    ⇔ 48x – 16 = 30
    ⇔ 48x = 46
    ⇔ x = 23/24
    b) (x+4)^2 – (x+1) (x-1) = 16
    ⇔ (x^2+8x+16) – (x^2-1) = 16
    ⇔ x^2 + 8x + 16 – x^2 + 1 = 16
    ⇔ 8x + 17 = 16
    ⇔ 8x = -1
    ⇔ x = -1/9

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222-9+11+12:2*14+14 = ? ( )