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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: Ai giúp em với ạ y=5sinxcosx−1

Toán Lớp 11: Ai giúp em với ạ
y=5sinxcosx−1

Comments ( 1 )

  1. Giải đáp:
    $max_y=\dfrac{3}{2} \Leftrightarrow x=\dfrac{\pi}{4}+k \pi(k \in \mathbb{Z}) \\ min_y=-\dfrac{7}{2} \Leftrightarrow x=-\dfrac{\pi}{4}+k \pi(k \in \mathbb{Z}) .$
    Lời giải và giải thích chi tiết:
    $y=5\sin x\cos x-1\\ =\dfrac{5}{2}.2\sin x\cos x-1\\ =\dfrac{5}{2}\sin 2x-1\\ -1 \le \sin 2x \le 1\\ \Rightarrow -\dfrac{5}{2} \le \dfrac{5}{2}\sin 2x \le \dfrac{5}{2}\\ \Rightarrow -\dfrac{7}{2} \le \dfrac{5}{2}\sin 2x-1 \le \dfrac{3}{2}\\ \Leftrightarrow -\dfrac{7}{2} \le y \le \dfrac{3}{2}\\ \Rightarrow max_y=\dfrac{3}{2} \Leftrightarrow \sin 2x=1 \Leftrightarrow  2x=\dfrac{\pi}{2}+k 2 \pi(k \in \mathbb{Z}) \Leftrightarrow  x=\dfrac{\pi}{4}+k \pi(k \in \mathbb{Z}) \\ min_y=-\dfrac{7}{2} \Leftrightarrow \sin 2x=-1 \Leftrightarrow  2x=\dfrac{-\pi}{2}+k 2 \pi(k \in \mathbb{Z}) \Leftrightarrow  x=-\dfrac{\pi}{4}+k \pi(k \in \mathbb{Z}) .$

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222-9+11+12:2*14+14 = ? ( )

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