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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: x + 1 = (x + 1)^2 tìm x GIẢI TRI TIẾT Ạ

Toán Lớp 8: x + 1 = (x + 1)^2 tìm x
GIẢI TRI TIẾT Ạ

Comments ( 2 )

  1. x + 1 = (x +1)²
    ⇔ x + 1 = x² + 2x + 1
    ⇔ x² + 2x + 1 – x – 1 = 0
    ⇔ x² – x = 0
    ⇔ x (x – 1) = 0
    Có 2 TH:
    – TH1 : x = 0
    – TH2 : x – 1 = 0 ⇔ x = 1
    Vậy S ∈ 0, 1
     

  2. #kehuydiet
    $(x+1)^2=x+1$
    $⇔ x^2+2x+1=x+1$
    $⇔ x^2+x=0$
    $⇔ x(x+1)=0$
    $⇔ x=0$ hoặc $x=-1$
    Vậy $S=\{0;-1\}$

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222-9+11+12:2*14+14 = ? ( )