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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: `(5^10 . 7^3 -25^5 .49^2)/( (125.7)^3 +5^9 .14^3)`

Home/ Toán Lớp 7: `(5^10 . 7^3 -25^5 .49^2)/( (125.7)^3 +5^9 .14^3)`

Toán Lớp 7: `(5^10 . 7^3 -25^5 .49^2)/( (125.7)^3 +5^9 .14^3)`

Tháng Mười 15, 2022 Toán học 2 Comments 0 views

Toán Lớp 7: (5^10 . 7^3 -25^5 .49^2)/( (125.7)^3 +5^9 .14^3)

Comments ( 2 )

  1. thuminhthong
    thuminhthong
    15 Tháng Mười, 2022 at 10:08 sáng
    Reply
    $\dfrac{5^{10}.7^{3}-25^{5}.49^2}{(125.7)^3+5^9.14^3}$
    =$\dfrac{5^{10}.7^{3}-5^{10}.7^4}{(5^3 .7)^3+5^9.2^3 . 7^3}$
    =$\dfrac{5^{10}.7^{3}.(1-7)}{5^9 . 7^3+5^9.2^3 . 7^3}$
    =$\dfrac{5^{10}.7^{3}.(-6)}{5^9 . 7^3.(1+2^3)}$
    =$\dfrac{5^{9}.5.7^{3}.(-6)}{5^9 . 7^3.9}$
    =$\dfrac{5.(-6)}{9}$
    =$\dfrac{-30}{9}$
    =$\dfrac{-10}{3}$

  2. quynhthanhnghi
    quynhthanhnghi
    15 Tháng Mười, 2022 at 10:07 sáng
    Reply
    (5^10 .7^3 -25^5 .49^2)/((125 .7)^3 + 5^9 . 14^3)
    = (5^10 .7^3 -(5^2)^5 .(7^2)^2)/((5^3 .7)^3 + 5^9 . 2^3 . 7^3)
    = (5^10 .7^3 -5^10 .7^4)/(5^9 .7^3 + 5^9 . 2^3 . 7^3)
    = (5 . 1 – 5 . 7)/(1.1 + 1 . 8 . 1)
    = (5.(1-7))/(1+8)
    = (5 . (-6))/9
    = -30/9
    = -10/3

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222-9+11+12:2*14+14 = ? ( )

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