Toán Lớp 6: (x-2)+y(x-2)=4
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Toán Lớp 6: (x-2)+y(x-2)=4
giúp mình vớiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
Comments ( 2 )
(x-2)+y(x-2)= 4
=> (x-2)(y+1)= 4
=>$\left[\begin{matrix} x-2= 4\\ y+1= 4\end{matrix}\right.$
=> $\left[\begin{matrix} x= 6\\ x= 3\end{matrix}\right.$
Vậy x∈{6; 3}
Đáp án: + Lời giải và giải thích chi tiết:
$\text{(x -2 ) + y(x-2) = 4}$
$\text{(x-2) ( y+1) = 4}$
Vậy ta có
$\begin{cases} y + 1 = 4\\ x – 2 = 4\\ \end{cases}$
$\begin{cases} x = 6\\x = 3\\ \end{cases}$
x E $\text{{6;3}}$