Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm n thuộc z thỏa mãn5n-1 chia hết 3n+2

Toán Lớp 6: tìm n thuộc z thỏa mãn5n-1 chia hết 3n+2

Comments ( 2 )

  1. Vì n∈ Z => 5n – 1; 3n + 2 ∈ Z
    => 5n – 1 vdots 3n + 2 <=> 15n – 3 vdots 3n + 2
    <=> (15n + 10 ) – (5n – 1) vdots 3n + 2
    <=> 15n + 10 – 15n + 3 vdots 3n + 2
    => 13 vdots 3n + 2
    => 3n + 2 ∈ Ư(13) = {-13;-1;1;13}
    => 3n ∈ {-15;-3;-1;11}
    => n ∈ {-5;-1;-1/3;11/3}
    Mà n ∈ Z => n ∈ {-5;-1}
    Vậy n ∈ {-5;-1} => 5n – 1 vdots 3n + 2

  2. Do n ∈ Z => 5n – 1; 3n + 2 ∈ Z
    5n – 1 vdots 3n + 2
    <=> 15n – 3 vdots 3n + 2
    Ta có: 3n + 2 vdots 3n + 2
    <=> 15n + 10 vdots 3n + 2
    <=> (15n + 10 ) – (5n – 1) vdots 3n + 2
    <=> 15n + 10 – 15n + 3 vdots 3n + 2
    <=> 13 vdots 3n + 2
    <=> 3n + 2 ∈ Ư(13) = {-13;-1;1;13}
    <=> 3n ∈ {-15;-3;-1;11}
    <=> n ∈ {-5;-1;-1/3;11/3}
    mà n ∈ Z
    => n ∈ {-5;-1}
    Vậy n ∈ {-5;-1} thì 5n – 1 vdots 3n + 2

Leave a reply

222-9+11+12:2*14+14 = ? ( )