Toán học Toán Lớp 8: Phân tích đa thức sau thành nhân tử : (x+2)(x+3)(x+4)(x+5)-8 19 Tháng Sáu, 2022 By Nhiên Toán Lớp 8: Phân tích đa thức sau thành nhân tử : (x+2)(x+3)(x+4)(x+5)-8
(x+2).(x+3).(x+4).(x+5)-8 =(x+2).(x+5).(x+3).(x+4)-8 =(x^2+5x+2x+10).(x^2+4x+3x+12)-8 =(x^2+7x+10).(x^2+7x+12)-8 =(x^2+7x+11-1).(x^2+7x+11+1)-8 =(x^2+7x+11)^2-1^2-8 =(x^2+7x+11)^2-9 =(x^2+7x+11)^2-3^2 =(x^2+7x+11-3).(x^2+7x+11+3) =(x^2+7x+8).(x^2+7x+14) $#chúc tus học tốt!!$ #La Trả lời
\left(x^{2}+3x+2x+6\right)\left(x+4\right)\left(x+5\right)-8 \left(x^{3}+4x^{2}+5x^{2}+20x+6x+24\right)\left(x+5\right)-8 \left(x^{2}+5x+6\right)\left(x+4\right)\left(x+5\right)-8 \left(x^{3}+9x^{2}+20x+6x+24\right)\left(x+5\right)-8 x^{4}+5x^{3}+9x^{3}+45x^{2}+26x^{2}+130x+24x+120-8 \left(x^{3}+9x^{2}+26x+24\right)\left(x+5\right)-8 x^{4}+14x^{3}+45x^{2}+26x^{2}+130x+24x+120-8 x^{4}+14x^{3}+71x^{2}+130x+24x+120-8 x^{4}+14x^{3}+71x^{2}+154x+112 Trả lời
\left(x^{2}+3x+2x+6\right)\left(x+4\right)\left(x+5\right)-8 \left(x^{3}+4x^{2}+5x^{2}+20x+6x+24\right)\left(x+5\right)-8 \left(x^{2}+5x+6\right)\left(x+4\right)\left(x+5\right)-8 \left(x^{3}+9x^{2}+20x+6x+24\right)\left(x+5\right)-8 x^{4}+5x^{3}+9x^{3}+45x^{2}+26x^{2}+130x+24x+120-8 \left(x^{3}+9x^{2}+26x+24\right)\left(x+5\right)-8 x^{4}+14x^{3}+45x^{2}+26x^{2}+130x+24x+120-8 x^{4}+14x^{3}+71x^{2}+130x+24x+120-8 x^{4}+14x^{3}+71x^{2}+154x+112