Toán học Toán Lớp 7: $\frac{32^{3} – 9^{5}}{8^3 – 6^6}$ Giups mik vs ạ 19 Tháng Sáu, 2022 By Ðan Khanh Toán Lớp 7: $\frac{32^{3} – 9^{5}}{8^3 – 6^6}$ Giups mik vs ạ
$\frac{32^{3}-9^{5} }{8^{3}-6^{6} }$ =$\frac{(2^{5})^{3}-(3^{2})^{5} }{(2^{3})^{3}-(2.3)^{6}}$ =$\frac{2^{15}-3^{10} }{2^{9}-2^{6}.3^{6}}$ =$3^{4}$ =81 #CHÚCBẠNHỌCTỐT^^ #tgiaphuc23122009 Trả lời
Ron \frac{32^{3} – 9^{5}}{8^{3} – 6^{6}}= \frac{(2^{5})^{3} – (3^{2})^{5}}{(2^{3})^{3} – (2 . 3)^{6}}= \frac{2^{15} – 3^{10}}{2^{9} – 2^{6} . 3^{6}= \frac{2^{6} – 3^{4}}{2^{6}= \frac{3^{4}}{1}= 81 Trả lời
= \frac{(2^{5})^{3} – (3^{2})^{5}}{(2^{3})^{3} – (2 . 3)^{6}}
= \frac{2^{15} – 3^{10}}{2^{9} – 2^{6} . 3^{6}
= \frac{2^{6} – 3^{4}}{2^{6}
= \frac{3^{4}}{1}
= 81