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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm x a.x+36=6 b.96-3(x+1)=42 c.(2x-1)(x+2)=0

Toán Lớp 6: tìm x
a.x+36=6
b.96-3(x+1)=42
c.(2x-1)(x+2)=0

Comments ( 2 )

  1. a.x+36=6
    x = 6 – 36
    x = -30
    b.96-3(x+1)=42
    3(x+1) = 96 – 42
    3(x+1) = 54
    x+1 = 54 : 3
    x+1 = 18
    x = 18 – 1 = 17
    c.(2x-1)(x+2)=0
    TH1: 2x-1 = 0
    2x = 0 + 1 = 1
    x = 1 : 2 = $\frac{1}{2}$ 
    TH2: x+2 = 0
    x = 0 – 2 = -2
    => x ∈ { $\frac{1}{2}$ ; -2}

  2. $a)x+36=6$
    $x=6-36$
    $x=-30$
    $b)96-3(x+1)=42$
    $96-3x-3=42$
    $93-3x=42$
    $3x=51$
    $x=51:3$
    $=17$
    $c)(2x-1)(x+2)=0$
    \(\left[ \begin{array}{l}2x-1=0\\x+2=0\end{array} \right.\)
    \(\left[ \begin{array}{l}2x=1\\x=-2\end{array} \right.\)
    \(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=-2\end{array} \right.\)
    Vậy $x$ ∈ {$\dfrac{1}{2};-2$}
    $#thanhmaii2008$
     

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222-9+11+12:2*14+14 = ? ( )

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