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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: cho biểu thức A= 2016+2016^2+2016^3+…+2016^2016 chứng minh rằng A chia hết cho 2017

Toán Lớp 6: cho biểu thức A= 2016+2016^2+2016^3+…+2016^2016
chứng minh rằng A chia hết cho 2017

Comments ( 2 )

  1. ~ Bạn tham khảo ~
    A = 2016 + 2016^2 + …. 2016^2015 + 2016^2016
    A = (2016+2016^2) + …… + (2016^2015 + 2016^2016)
    A = 2016 . ( 1 + 2016 )+……+ 2016^2015 . (1+2016)
    A = 2016 . 2017 + ……+ 2016^2015 + 2017
    A = 2017 . ( 2016 + …. + 2016^2015 )
    Mà 2017 vdots 2017
    Vậy A vdots 2017
    $#Vịt vàng$

  2. $\\$
    A=2016+2016^2+…+2016^{2015}+2016^{2016}
    = (2016+2016^2)+…+(2016^{2015}+2016^{2016})
    = 2016 (1+2016) + … + 2016^{2015}(1+2016)
    = 2016 . 2017 + … + 2016^{2015} . 2017
    = 2017 . (2016+…+2016^{2015})
    Do 2017\vdots 2017
    => 2017 . (2016 + … + 2016^{2015})\vdots 2017
    =>A\vdots 2017

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222-9+11+12:2*14+14 = ? ( )