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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn `((3+x)/(3-x)-(3-x)/(x+3)+(4x^2)/(x^2-9))*(2+x+(x^2+x-1)/(2-x))`

Tháng Tư 13, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: Rút gọn ((3+x)/(3-x)-(3-x)/(x+3)+(4x^2)/(x^2-9))*(2+x+(x^2+x-1)/(2-x))

Comments ( 1 )

  1. kimnguenoanh
    kimnguenoanh
    13 Tháng Tư, 2022 at 4:37 chiều
    Reply
    $\text{($\dfrac{3 + x}{3 – x}$ – $\dfrac{3 – x}{x + 3}$ + $\dfrac{4x^{2}}{x^{2} – 9}$) . (2 + x + $\dfrac{x^{2} + x – 1}{2 – x}$) Đkxđ: x $\neq$ ±3; x $\neq$ 2}$
    $\text{= ($\dfrac{3 + x}{3 – x}$ – $\dfrac{3 – x}{3 + x}$ – $\dfrac{4x^{2}}{9 – x^{2}}$) . $\dfrac{(2 + x)(2 – x) + (x^{2} + x – 1)}{2 – x}$}$
    $\text{= $\dfrac{(3 + x)(3 + x) – (3 – x)(3 – x) – 4x^{2}}{(3 – x)(3 + x)}$ . $\dfrac{4 – x^{2} + x^{2} + x – 1}{2 – x}$}$
    $\text{= $\dfrac{9 + 6x + x^{2} – 9 + 6x – x^{2} – 4x^{2}}{(3 – x)(3 + x)}$ . $\dfrac{x + 3}{2 – x}$}$
    $\text{= $\dfrac{12x – 4x^{2}}{(3 – x)(3 + x)}$ . $\dfrac{x + 3}{2 – x}$}$
    $\text{= $\dfrac{4x(3 – x)}{(3 – x)(3 + x)}$ . $\dfrac{x + 3}{2 – x}$}$
    $\text{= $\dfrac{4x}{2 – x}$}$
    $\textit{Ha1zzz}$
     

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222-9+11+12:2*14+14 = ? ( )

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