Toán Lớp 8: làm phép chia (3x^3-8x^+7x-6):(x-2)
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Toán Lớp 8: làm phép chia (3x^3-8x^+7x-6):(x-2)
Comments ( 1 )
3{x^3} – 8{x^2} + 7x – 6\\
= 3{x^3} – 6{x^2} – 2{x^2} + 4x + 3x – 6\\
= 3{x^2}\left( {x – 2} \right) – 2x\left( {x – 2} \right) + 3\left( {x – 2} \right)\\
= \left( {x – 2} \right)\left( {3{x^2} – 2x + 3} \right)\\
\Leftrightarrow \left( {3{x^3} – 8{x^2} + 7x – 6} \right):\left( {x – 2} \right)\\
= \left( {x – 2} \right)\left( {3{x^2} – 2x + 3} \right):\left( {x – 2} \right)\\
= 3{x^2} – 2x + 3
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