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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Cho x+y=1 Tinh gia tri bieu thuc A=x mu 3 +3xy+y mu 3 + 2020

Toán Lớp 8: Cho x+y=1
Tinh gia tri bieu thuc A=x mu 3 +3xy+y mu 3 + 2020

Comments ( 2 )

  1. $x^{3}+3xy+y^{3}+2020$
    $=(x^{3}+y^{3})+3xy+2020$
    $=(x+y)(x^{2}-xy+y^{2})+3xy+2020$
    Thay $x+y=1$
    $=x^{2}-xy+y^{2}+3xy+2020$
    $=x^{2}+2xy+y^{2}+2020$
    $=(x+y)^{2}+2020$
    Thay $x+y=1$
    $=1+2020$
    $=2021$
    Vậy bằng $2021$

  2. $\textit{Giải đáp + Lời giải và giải thích chi tiết:}$
    $A = x^3+3xy+y^3+2020$
    $A = (x+y)(x^2-xy+y^2)+3xy+2020$
    $A = 1 . x^2-xy+y^2+3xy+2020$
    $A = x^2-2xy+y^2+2020$
    $A = (x+y)^2+2020$
    $A = 1^2 + 2020$
    $A = 2021$
     

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222-9+11+12:2*14+14 = ? ( )

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