Toán Lớp 7: tìm x biết l4x-1l-l3x-1/2l=0 giúp mik nhé mik đang cần gấp
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TRẢ LỜI ( 1 )
x = \dfrac{3}{{11}}\\
x = \dfrac{1}{5}
\end{array} \right.\)
\left| {4x – 1} \right| – \left| {\dfrac{{3x – 1}}{2}} \right| = 0\\
\to \left| {4x – 1} \right| = \left| {\dfrac{{3x – 1}}{2}} \right|\\
\to \left[ \begin{array}{l}
4x – 1 = \dfrac{{3x – 1}}{2}\left( {DK:x \ge \dfrac{1}{3}} \right)\\
4x – 1 = – \dfrac{{3x – 1}}{2}\left( {DK:\dfrac{1}{3} > x \ge \dfrac{1}{4}} \right)\\
– 4x + 1 = – \dfrac{{3x – 1}}{2}\left( {DK:x < \dfrac{1}{4}} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
8x – 2 = 3x – 1\\
8x – 2 = – 3x + 1\\
– 8x + 2 = – 3x + 1
\end{array} \right.\\
\to \left[ \begin{array}{l}
5x = 1\\
11x = 3\\
5x = 1
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{3}{{11}}\\
x = \dfrac{1}{5}
\end{array} \right.
\end{array}\)