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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Cho $\dfrac{x}{3}$ = $\dfrac{y}{5}$ . Tính giá trị biểu thức A = $\dfrac{$5x^{2}$ + $3y^{2}$}{$10^{2}$ – $3y^{2}$ }$

Toán Lớp 7: Cho $\dfrac{x}{3}$ = $\dfrac{y}{5}$ . Tính giá trị biểu thức A = $\dfrac{$5x^{2}$ + $3y^{2}$}{$10^{2}$ – $3y^{2}$ }$

Comments ( 2 )

  1. Đặt $\dfrac{x}{3}$ = $\dfrac{y}{5}$ =k (k $\neq$ 0)
    ⇒ $\begin{cases} x=3k\\y=5k \end{cases}$
    A= $\dfrac{5x^2+3y^2}{10x^2-3y^2}$
      = $\dfrac{5(3k)^2+3(5k)^2}{10(3k)^2-3(5k)^2}$
      = $\dfrac{45k^2+75k^2}{90k^2-75k^2}$
      = $\dfrac{(45+75)k^2}{(90-75)k^2}$
      = $\dfrac{120}{15}$ =8
    Vậy A=8

  2. Đặt:
    x/3 = y/5 = k
    => x = 3k, y = 5k
    Có:
    A = (5x^2 + 3y^2)/(10x^2 – 3y^2)
    A = (5 . (3k)^2 + 3 . (5k)^2 )/(10 . (3k)^2 – 3 . (5k)^2)
    A = (45k^2 + 75k^2)/(90k^2 – 75k^2)
    A = (k^2 (45 + 75) )/(k^2 (90 – 75) )
    A = 120/15
    A = 8
    Vậy A = 8

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222-9+11+12:2*14+14 = ? ( )