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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: bài 5 tìm x

Toán Lớp 6: bài 5 tìm x b. 6.x³ – 8 = 40 c. ( x – 1 ) ³ = 9³ d. ( x – 1 ) ² = 25 e. ( 2x + 1) ³ = 125 f. ( 2x + 4 ) ³ = 64
Bài 7: Tìm x, biết:
a) 230 + [24 + (x – 5)] = 315. 20180 ; b) 707: [(2x – 5) + 74] = 42 – 32;
c) [(6x – 12): 3].32 = 64; d) (x:7 + 15).23 = 391

Comments ( 2 )

  1. Đáp án:
     
    Giải thích các bước giải:
     

    toan-lop-6-bai-5-tim

  2. Bài 5:
    b)6.x³-8=40
    ⇒6·x³=40+8
    ⇒6.x³=48
    ⇒x³=48:6
    ⇒x³=8
    ⇒x³=2³
    ⇒x=3
    c)(x-1)³=9³
    ⇒x-1=9
    ⇒x=9+1
    ⇒x=10
    d)(x-1)²=25
    ⇒(x-1)²=5²
    ⇒x-1=±5
    ⇒\(\left[ \begin{array}{l}x-1=5\\x-1=-5\end{array} \right.\) 
    ⇒\(\left[ \begin{array}{l}x=6\\x=-4\end{array} \right.\) 
    ⇒x ∈ {6,-4}
    e)(2x+4)³=125
    ⇒(2x+4)³=5³
    ⇒2x+4=5
    ⇒2x=1
    ⇒x=$\dfrac{1}{2}$
    Bài 7:
    a)230+[24+(x-5)=312.20180
    ⇒230+[24+(x-5)=6296160
    ⇒24+(x-5)=6296160-230
    ⇒24+(x-5)=6295930
    ⇒x-5=6295930-24
    ⇒x-5=6295906
    ⇒x=6295911
    b)707: [(2x – 5) + 74] = 42 – 32;
    ⇒707:[(2x-5)+74]=10
    ⇒(2x-5)+74=707:10
    ⇒(2x-5)+74=$\dfrac{707}{10}$
    ⇒2x-5=$\dfrac{707}{10}$-74
    ⇒2x-5=$\dfrac{-33}{10}$
    ⇒2x=$\dfrac{-33}{10}$+5
    ⇒2x=$\dfrac{17}{10}$
    ⇒x=$\dfrac{17}{20}$
    c)[(6x – 12): 3].32 = 64
    ⇒(6x-12):3=64:32
    ⇒(6x-12):3=2
    ⇒6x-12=3·2
    ⇒6x-12=6
    ⇒6x=6+12
    ⇒6x=18
    ⇒x=3
    d)(x:7 + 15).23 = 391
    ⇒x:7+15=391:23
    ⇒x:7+15=17
    ⇒x:7=17-15
    ⇒x:7=2
    ⇒x=2·7
    ⇒x=14
     

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222-9+11+12:2*14+14 = ? ( )